Function sum_of_divisors

project_euler/problem_021/sol1.py:20–27

(n: int)

def sum_of_divisors(n: int) -> int:
    total = 0
    for i in range(1, int(sqrt(n) + 1)):
        if n % i == 0 and i != sqrt(n):
            total += i + n // i
        elif i == sqrt(n):
            total += i
    return total - n


def solution(n: int = 10000) -> int: