(nums []int)
| 8 | package permutation |
| 9 | |
| 10 | func NextPermutation(nums []int) { |
| 11 | pivot := 0 |
| 12 | for pivot = len(nums) - 2; pivot >= 0; pivot-- { |
| 13 | if nums[pivot] < nums[pivot+1] { |
| 14 | break |
| 15 | } |
| 16 | } |
| 17 | if pivot < 0 { |
| 18 | // current permutation is the last and must be reversed totally |
| 19 | for l, r := 0, len(nums)-1; l < r; l, r = l+1, r-1 { |
| 20 | nums[l], nums[r] = nums[r], nums[l] |
| 21 | } |
| 22 | } else { |
| 23 | succ := 0 |
| 24 | for succ = len(nums) - 1; succ > pivot; succ = succ - 1 { |
| 25 | if nums[succ] > nums[pivot] { |
| 26 | break |
| 27 | } |
| 28 | } |
| 29 | |
| 30 | // Swap the pivot and successor |
| 31 | nums[pivot], nums[succ] = nums[succ], nums[pivot] |
| 32 | |
| 33 | // Reverse the suffix part to minimize it |
| 34 | for l, r := pivot+1, len(nums)-1; l < r; l, r = l+1, r-1 { |
| 35 | nums[l], nums[r] = nums[r], nums[l] |
| 36 | } |
| 37 | } |
| 38 | |
| 39 | } |
no outgoing calls