(arr: &mut Vec<i32>)
| 2 | // 因为最后一个元素是要被挤出去的那一个 |
| 3 | |
| 4 | pub fn duplicate_zeros(arr: &mut Vec<i32>) { |
| 5 | let mut i = 0; |
| 6 | while i < arr.len() { |
| 7 | if arr[i] == 0 { |
| 8 | for j in (i+1..arr.len()).rev() { |
| 9 | let tmp = arr[j]; |
| 10 | arr[j] = arr[j-1]; |
| 11 | arr[j-1] = tmp; |
| 12 | } |
| 13 | arr[i] = 0; |
| 14 | i+=1; |
| 15 | } |
| 16 | i+=1; |
| 17 | } |
| 18 | } |
| 19 | |
| 20 | fn main() { |
| 21 | let mut arr = vec![1,0,2,3,0,4,5,0]; |