Function _unpack_zipfile

Lib/shutil.py:1309–1337

Unpack zip `filename` to `extract_dir`

(filename, extract_dir)

        os.makedirs(dirname)

def _unpack_zipfile(filename, extract_dir):
    """Unpack zip `filename` to `extract_dir`
    """
    import zipfile  # late import for breaking circular dependency

    if not zipfile.is_zipfile(filename):
        raise ReadError("%s is not a zip file" % filename)

    zip = zipfile.ZipFile(filename)
    try:
        for info in zip.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name:
                continue

            targetpath = os.path.join(extract_dir, *name.split('/'))
            if not targetpath:
                continue

            _ensure_directory(targetpath)
            if not name.endswith('/'):
                # file
                with zip.open(name, 'r') as source, \
                        open(targetpath, 'wb') as target:
                    copyfileobj(source, target)
    finally:
        zip.close()

def _unpack_tarfile(filename, extract_dir, *, filter=None):
    """Unpack tar/tar.gz/tar.bz2/tar.xz/tar.zst `filename` to `extract_dir`