Function solution

String_containing_binary.py:3–22

(s)

""" 1st Approach """

def solution(s):   
    # Converting binary string to decimal   
    decimal_number = int(s, 2)    
    
    # Defining variable to count no of operations required   
    operations_count = 0    

    # loopping until decimal number becomes 0   
    while decimal_number > 0:     
        # if Even, divide the number by 2     
        if decimal_number % 2 == 0:       
            decimal_number /= 2     
        # if Odd, subtract 1 from it     
        else:       
            decimal_number -= 1     
        # incrementing operations count by 1     
        operations_count += 1   
    return operations_count  
    
    # validating solution function 
print("solution('011100'):", solution('011100')) 
print("solution('111'):", solution('111')) 
print("solution('1111010101111'):", solution('1111010101111'))