Function urlparse

tools/python-3.11.9-amd64/Lib/urllib/parse.py:374–402

Parse a URL into 6 components: :// / ; ? # The result is a named 6-tuple with fields corresponding to the above. It is either a ParseResult or ParseResultBytes object, depending on the type of the url parameter. The username, pa

(url, scheme='', allow_fragments=True)

del _fix_result_transcoding

def urlparse(url, scheme='', allow_fragments=True):
    """Parse a URL into 6 components:
    <scheme>://<netloc>/<path>;<params>?<query>#<fragment>

    The result is a named 6-tuple with fields corresponding to the
    above. It is either a ParseResult or ParseResultBytes object,
    depending on the type of the url parameter.

    The username, password, hostname, and port sub-components of netloc
    can also be accessed as attributes of the returned object.

    The scheme argument provides the default value of the scheme
    component when no scheme is found in url.

    If allow_fragments is False, no attempt is made to separate the
    fragment component from the previous component, which can be either
    path or query.

    Note that % escapes are not expanded.
    """
    url, scheme, _coerce_result = _coerce_args(url, scheme)
    splitresult = urlsplit(url, scheme, allow_fragments)
    scheme, netloc, url, query, fragment = splitresult
    if scheme in uses_params and ';' in url:
        url, params = _splitparams(url)
    else:
        params = ''
    result = ParseResult(scheme, netloc, url, params, query, fragment)
    return _coerce_result(result)

def _splitparams(url):
    if '/'  in url: