Method _get_filename_node

tables/link.py:391–395

Return the external filename and nodepath from `self.target`.

(self)

        super().__init__(parentnode, name, target, _log)

    def _get_filename_node(self) -> tuple[str, str]:
        """Return the external filename and nodepath from `self.target`."""
        # This is needed for avoiding the 'C:\\file.h5' filepath notation
        filename, target = self.target.split(":/")
        return filename, "/" + target

    def __call__(self, **kwargs) -> Node:
        """Dereference self.target and return the object.