Function resolve_default_class_name

src/parser/mod.rs:969–994

Resolve a class name from a parameter default (`Foo::class`) to its FQN using the file's use-map and namespace from [`DocblockCtx`].

(name: &str, doc_ctx: Option<&DocblockCtx<'_>>)

/// Resolve a class name from a parameter default (`Foo::class`) to its FQN
/// using the file's use-map and namespace from [`DocblockCtx`].
fn resolve_default_class_name(name: &str, doc_ctx: Option<&DocblockCtx<'_>>) -> String {
    // Already fully-qualified.
    if let Some(stripped) = name.strip_prefix('\\') {
        return stripped.to_string();
    }
    let Some(ctx) = doc_ctx else {
        return name.to_string();
    };
    // Check use-map (handles `use App\Application;` → "Application" → "App\Application").
    if let Some(fqn) = ctx.use_map.get(name) {
        return fqn.clone();
    }
    // If the name has a namespace prefix (e.g. `Sub\Foo`), check the first segment.
    if let Some(first_seg) = name.split('\\').next()
        && first_seg != name
        && let Some(base) = ctx.use_map.get(first_seg)
    {
        let rest = &name[first_seg.len() + 1..];
        return format!("{}\\{}", base, rest);
    }
    // Prepend file namespace if present.
    if let Some(ref ns) = ctx.namespace {
        return format!("{}\\{}", ns, name);
    }
    name.to_string()
}

/// Extract visibility from a set of modifiers.
/// Defaults to `Public` if no visibility modifier is present.