Function is_variable_assignment

src/completion/phpdoc/context.rs:531–550

Check whether a trimmed code line is a simple variable assignment. Returns `true` for lines like `$foo = expr;` or `$foo = expr` (no semicolon yet). Returns `false` for method calls (`$foo->bar()`), comparisons (`$foo == bar`), and other non-assignment uses.

(line: &str)

/// semicolon yet).  Returns `false` for method calls (`$foo->bar()`),
/// comparisons (`$foo == bar`), and other non-assignment uses.
fn is_variable_assignment(line: &str) -> bool {
    // Find the first `$` — start of the variable name.
    let Some(dollar) = line.find('$') else {
        return false;
    };
    // Skip past the variable name (alphanumeric, `_`, `$`).
    let after_name = &line[dollar..];
    let name_len = after_name
        .chars()
        .take_while(|c| c.is_alphanumeric() || *c == '_' || *c == '$')
        .count();
    let rest = after_name[name_len..].trim_start();

    // Must start with `=` but not `==` or `=>`.
    if let Some(stripped) = rest.strip_prefix('=') {
        !stripped.starts_with('=') && !stripped.starts_with('>')
    } else {
        false
    }
}

/// Check if a token is a PHP type keyword (used in property declarations).
fn is_type_keyword(token: &str) -> bool {