Function double2lldiv_t

strings/decimal.c:1152–1182

Convert double value to lldiv_t valie. @param from The double value to convert from. @param OUT to The lldit_t variable to convert to. @return 0 on success, error code on error. Integer part goes into lld.quot. Fractional part multiplied to 1000000000 (10^9) goes to lld.rem. Typically used in datetime calculations to split seconds and nanoseconds. */

  and nanoseconds.
*/
int double2lldiv_t(double nr, lldiv_t *lld)
{
  if (nr > LLDIV_MAX)
  {
    lld->quot= LLDIV_MAX;
    lld->rem= 0;
    return E_DEC_OVERFLOW;
  }
  else if (nr < LLDIV_MIN)
  {
    lld->quot= LLDIV_MIN;
    lld->rem= 0;
    return E_DEC_OVERFLOW;
  }
  /* Truncate fractional part toward zero and store into "quot" */
  lld->quot= (longlong) (nr > 0 ? floor(nr) : ceil(nr));
  /* Multiply reminder to 10^9 and store into "rem" */
  lld->rem= (longlong) rint((nr - (double) lld->quot) * 1000000000);
  /*
    Sometimes the expression "(double) 0.999999999xxx * (double) 10e9"
    gives 1,000,000,000 instead of 999,999,999 due to lack of double precision.
    The callers do not expect lld->rem to be greater than 999,999,999.
    Let's catch this corner case and put the "nanounit" (e.g. nanosecond)
    value in ldd->rem back into the valid range.
  */
  if (lld->rem > 999999999LL)
    lld->rem= 999999999LL;
  else if (lld->rem < -999999999LL)
    lld->rem= -999999999LL;
  return E_DEC_OK;
}