Function _ordinal_suffix

kittentts/preprocess.py:203–228

Return the ordinal word for n (e.g. 1 → 'first', 5 → 'fifth', 21 → 'twenty-first').

(n: int)

# ─────────────────────────────────────────────

def _ordinal_suffix(n: int) -> str:
    """Return the ordinal word for n (e.g. 1 → 'first', 5 → 'fifth', 21 → 'twenty-first')."""
    word = number_to_words(n)
    # For hyphenated compounds like "twenty-one", convert only the last part
    if "-" in word:
        prefix, last = word.rsplit("-", 1)
        joiner = "-"
    else:
        parts = word.rsplit(" ", 1)
        prefix, last, joiner = (parts[0], parts[1], " ") if len(parts) == 2 else ("", parts[0], "")

    # Check exception table
    for base, ordinal in _ORDINAL_EXCEPTIONS.items():
        if last == base:
            last_ord = ordinal
            break
    else:
        # General rule
        if last.endswith("t"):
            last_ord = last + "h"
        elif last.endswith("e"):
            last_ord = last[:-1] + "th"
        else:
            last_ord = last + "th"

    return f"{prefix}{joiner}{last_ord}" if prefix else last_ord


def expand_ordinals(text: str) -> str: