Method get_simplest_request

integuru/agent.py:251–290

Find the index of the simplest cURL command from a list

(self, request_list: List[Request])

        return state

    def get_simplest_request(self, request_list: List[Request]) -> Request:
        """
        Find the index of the simplest cURL command from a list
        """
        function_def = {
            "name": "get_simplest_curl_index",
            "description": "Find the index of the simplest cURL command from a list",
            "parameters": {
                "type": "object",
                "properties": {
                    "index": {
                        "type": "integer",
                        "description": "The index of the simplest cURL command in the list"
                    }
                },
                "required": ["index"]
            }
        }
        # convert request objects to strings
        serializable_list = [str(req) for req in request_list]

        prompt = f"""
        {json.dumps(serializable_list)}
        Task:
        Given the above list of cURL commands, find the index of the curl that has the least number of dependencies and variables.
        The index should be 0-based (i.e., the first item has index 0).
        """

        response = llm.get_instance().invoke(
            prompt,
            functions=[function_def],
            function_call={"name": "get_simplest_curl_index"}
        )

        function_call = response.additional_kwargs['function_call']
        simplest_curl_index = json.loads(function_call['arguments'])['index']
        
        # Retrieve the actual cURL command using the index
        simplest_curl = request_list[simplest_curl_index]
        return simplest_curl

    def find_curl_from_content(self, state: AgentState) -> AgentState:
        """