Method upload_file_gui

cli/cli_interface.py:234–295

Enhanced file upload interface with better error handling

(self)

        return input().strip().lower()

    def upload_file_gui(self) -> Optional[str]:
        """Enhanced file upload interface with better error handling"""
        if not self.tkinter_available:
            self.print_status(
                "GUI file dialog not available - using manual input", "warning"
            )
            return self._get_manual_file_path()

        def select_file():
            try:
                import tkinter as tk
                from tkinter import filedialog

                root = tk.Tk()
                root.withdraw()
                root.attributes("-topmost", True)

                file_types = [
                    ("Research Papers", "*.pdf;*.docx;*.doc"),
                    ("PDF Files", "*.pdf"),
                    ("Word Documents", "*.docx;*.doc"),
                    ("PowerPoint Files", "*.pptx;*.ppt"),
                    ("HTML Files", "*.html;*.htm"),
                    ("Text Files", "*.txt;*.md"),
                    ("All Files", "*.*"),
                ]

                if platform.system() == "Darwin":
                    file_types = [
                        ("Research Papers", ".pdf .docx .doc"),
                        ("PDF Files", ".pdf"),
                        ("Word Documents", ".docx .doc"),
                        ("PowerPoint Files", ".pptx .ppt"),
                        ("HTML Files", ".html .htm"),
                        ("Text Files", ".txt .md"),
                        ("All Files", ".*"),
                    ]

                file_path = filedialog.askopenfilename(
                    title="Select Research File - DeepCode CLI",
                    filetypes=file_types,
                    initialdir=os.getcwd(),
                )

                root.destroy()
                return file_path

            except Exception as e:
                self.print_status(f"File dialog error: {str(e)}", "error")
                return self._get_manual_file_path()

        self.print_status("Opening file browser dialog...", "upload")
        file_path = select_file()

        if file_path:
            self.print_status(
                f"File selected: {os.path.basename(file_path)}", "success"
            )