Function parse_dependency_file

ci/wasm_compile_pch.py:120–202

Parse a .d dependency file and extract all dependency paths. Args: depfile: Path to .d dependency file Returns: List of dependency file paths (excluding the target itself)

(depfile: Path)

def parse_dependency_file(depfile: Path) -> list[Path]:
    """
    Parse a .d dependency file and extract all dependency paths.

    Args:
        depfile: Path to .d dependency file

    Returns:
        List of dependency file paths (excluding the target itself)
    """
    if not depfile.exists():
        return []

    try:
        with open(depfile, "r", encoding="utf-8") as f:
            lines = f.readlines()

        # Dependency files have format: target: dep1 dep2 dep3 \
        #                                dep4 dep5 ...
        # The first line contains "target: [optional deps] \"
        # Subsequent lines contain more dependencies

        if not lines:
            return []

        # Parse first line to get target
        first_line = lines[0].rstrip("\r\n")

        # Find the separator ": " or ":\\" in the first line
        # (target paths may contain colons on Windows, e.g., C:/path)
        # Look for ": " pattern which separates target from deps
        sep_idx = first_line.find(": ")
        if sep_idx == -1:
            # Try ":\" pattern (no space before backslash)
            sep_idx = first_line.find(":\\")
            if sep_idx == -1:
                return []
            sep_len = 2  # Length of ":\\"
        else:
            sep_len = 2  # Length of ": "

        target_str = first_line[:sep_idx]
        target = Path(target_str.strip()).resolve()

        # Collect all dependency text from continuation lines
        # Line format: each line ends with " \" except the last one
        deps_text = first_line[sep_idx + sep_len :].rstrip()

        # Remove trailing backslash if present (line continuation)
        if deps_text.endswith("\\"):
            deps_text = deps_text[:-1]

        # Process continuation lines
        for line in lines[1:]:
            line_clean = line.rstrip("\r\n").strip()
            # Remove trailing backslash if present
            if line_clean.endswith("\\"):
                line_clean = line_clean[:-1].strip()