Check that best_effort flag works.
(node_factory, bitcoind)
| 2092 | @pytest.mark.openchannel('v1') |
| 2093 | @pytest.mark.developer("disconnect=... needs DEVELOPER=1") |
| 2094 | def test_multifunding_best_effort(node_factory, bitcoind): |
| 2095 | ''' |
| 2096 | Check that best_effort flag works. |
| 2097 | ''' |
| 2098 | disconnects = ["-WIRE_INIT", |
| 2099 | "-WIRE_ACCEPT_CHANNEL", |
| 2100 | "-WIRE_FUNDING_SIGNED"] |
| 2101 | l1 = node_factory.get_node() |
| 2102 | l2 = node_factory.get_node() |
| 2103 | l3 = node_factory.get_node(disconnect=disconnects) |
| 2104 | l4 = node_factory.get_node() |
| 2105 | |
| 2106 | l1.fundwallet(2000000) |
| 2107 | |
| 2108 | destinations = [{"id": '{}@localhost:{}'.format(l2.info['id'], l2.port), |
| 2109 | "amount": 50000}, |
| 2110 | {"id": '{}@localhost:{}'.format(l3.info['id'], l3.port), |
| 2111 | "amount": 50000}, |
| 2112 | {"id": '{}@localhost:{}'.format(l4.info['id'], l4.port), |
| 2113 | "amount": 50000}] |
| 2114 | |
| 2115 | for i, d in enumerate(disconnects): |
| 2116 | # Should succeed due to best-effort flag. |
| 2117 | l1.rpc.multifundchannel(destinations, minchannels=2) |
| 2118 | bitcoind.generate_block(6, wait_for_mempool=1) |
| 2119 | |
| 2120 | # Only l3 should fail to have channels. |
| 2121 | for node in [l1, l2, l4]: |
| 2122 | node.daemon.wait_for_log(r'to CHANNELD_NORMAL') |
| 2123 | |
| 2124 | # There should be working channels to l2 and l4. |
| 2125 | for ldest in [l2, l4]: |
| 2126 | inv = ldest.rpc.invoice(5000, 'i{}'.format(i), 'i{}'.format(i))['bolt11'] |
| 2127 | l1.rpc.pay(inv) |
| 2128 | |
| 2129 | # Function to find the SCID of the channel that is |
| 2130 | # currently open. |
| 2131 | # Cannot use LightningNode.get_channel_scid since |
| 2132 | # it assumes the *first* channel found is the one |
| 2133 | # wanted, but in our case we close channels and |
| 2134 | # open again, so multiple channels may remain |
| 2135 | # listed. |
| 2136 | def get_funded_channel_scid(n1, n2): |
| 2137 | peers = n1.rpc.listpeers(n2.info['id'])['peers'] |
| 2138 | assert len(peers) == 1 |
| 2139 | peer = peers[0] |
| 2140 | channels = peer['channels'] |
| 2141 | assert channels |
| 2142 | for c in channels: |
| 2143 | state = c['state'] |
| 2144 | if state in ('CHANNELD_AWAITING_LOCKIN', 'CHANNELD_NORMAL'): |
| 2145 | return c['short_channel_id'] |
| 2146 | assert False |
| 2147 | |
| 2148 | # Now close channels to l2 and l4, for the next run. |
| 2149 | l1.rpc.close(get_funded_channel_scid(l1, l2)) |
| 2150 | l1.rpc.close(get_funded_channel_scid(l1, l4)) |
| 2151 |
nothing calls this directly
no test coverage detected