Method parseControl

parse.go:891–927

(allowElseIf bool, context string)

}

func (t *Template) parseControl(allowElseIf bool, context string) (pos Pos, line int, set *SetNode, expression Expression, list, elseList *ListNode) {
	line = t.lex.lineNumber()

	expression = t.assignmentOrExpression(context)
	pos = expression.Position()
	if expression.Type() == NodeSet {
		set = expression.(*SetNode)
		if context != "range" {
			t.expect(itemSemicolon, context, "semicolon between assignment and expression")
			expression = t.expression(context, "expression after assignment")
		} else {
			expression = nil
		}
	}

	t.expectRightDelim(context)
	var next Node
	list, next = t.itemList(nodeElse, nodeEnd)
	if next.Type() == nodeElse {
		if allowElseIf && t.peek().typ == itemIf {
			// Special case for "else if". If the "else" is followed immediately by an "if",
			// the elseControl will have left the "if" token pending. Treat
			//	{{if a}}_{{else if b}}_{{end}}
			// as
			//	{{if a}}_{{else}}{{if b}}_{{end}}{{end}}.
			// To do this, parse the if as usual and stop at it {{end}}; the subsequent{{end}}
			// is assumed. This technique works even for long if-else-if chains.
			t.next() // Consume the "if" token.
			elseList = t.newList(next.Position())
			elseList.append(t.ifControl())
			// Do not consume the next item - only one {{end}} required.
		} else {
			elseList, _ = t.itemList(nodeEnd)
		}
	}
	return pos, line, set, expression, list, elseList
}

// If:
//