Function is_classifier_layer

utils/misc.py:23–26

Check if the layer is part of classifier based on common naming patterns

(name: str)

        Dictionary containing parameter counts in K (1000s)
    """
    def is_classifier_layer(name: str) -> bool:
        """Check if the layer is part of classifier based on common naming patterns"""
        classifier_keywords = ['classifier', 'fc', 'linear', 'head']
        return any(keyword in name.lower() for keyword in classifier_keywords)
    
    total_params = 0
    classifier_params = 0