| 1 | public class Knapsack { |
| 2 | public int knapsack(int cap, int[] weights, int[] values) { |
| 3 | int n = values.length; |
| 4 | // Base case: Set the first column and last row to 0 by |
| 5 | // initializing the entire DP table to 0. |
| 6 | int[][] dp = new int[n + 1][cap + 1]; |
| 7 | |
| 8 | // Populate the DP table. |
| 9 | for (int i = n - 1; i >= 0; i--) { |
| 10 | for (int c = 1; c < cap + 1; c++) { |
| 11 | // If the item 'i' fits in the current knapsack capacity, |
| 12 | // the maximum value at 'dp[i][c]' is the largest of either: |
| 13 | // 1. The maximum value if we include item 'i'. |
| 14 | // 2. The maximum value if we exclude item 'i'. |
| 15 | if (weights[i] <= c) { |
| 16 | dp[i][c] = Math.max(values[i] + dp[i + 1][c - weights[i]], dp[i + 1][c]); |
| 17 | } |
| 18 | // If it doesn't fit, we have to exclude it. |
| 19 | else { |
| 20 | dp[i][c] = dp[i + 1][c]; |
| 21 | } |
| 22 | } |
| 23 | } |
| 24 | return dp[0][cap]; |
| 25 | } |
| 26 | } |
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